1/3x^2-7/3x=-4

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Solution for 1/3x^2-7/3x=-4 equation: 


x in (-oo:+oo)

(1/3)*x^2-((7/3)*x) = -4 // + 4

(1/3)*x^2-((7/3)*x)+4 = 0

(1/3)*x^2+(-7/3)*x+4 = 0

1/3*x^2-7/3*x+4 = 0

DELTA = (-7/3)^2-(1/3*4*4)

DELTA = 1/9

DELTA > 0

x = ((1/9)^(1/2)+7/3)/(1/3*2) or x = (7/3-(1/9)^(1/2))/(1/3*2)

x = 4 or x = 3

x in { 3, 4 }

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